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Convert A Polaris Sight To Latitude

2009-04-24
Lại Trường Thọ
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Since Polaris is always within about 1° of the North Pole, the altitude of Polaris, with a few minor corrections, equals the latitude of the observer. This relationship makes Polaris an extremely important navigational star in the northern hemisphere.

The corrections are necessary because Polaris orbits in a small circle around the pole. When Polaris is at the exact same altitude as the pole, the correction is zero. At two points in its orbit it is in a direct line with the observer and the pole, either nearer than or beyond the pole. At these points the corrections are maximum. The nofollowing example illustrates converting a Polaris sight to latitude.

At 23-18-56 GMT, on April 21, 1994, at DR Lat. 50°23.8' N, λ=37° 14.0'W, the observed altitude of Polaris (h_o) is 49° 31.6'. Find the vessel’s latitude. To solve this problem, use the equation:

Latitude = h_o - 1^{\circ} + A_0 + A_1 + A_2

where h_o is the sextant altitude (h_s) corrected as in any other star sight; 1° is a constant; and A_0, A_1, and A_2 are correction factors from the Polaris tables found in the Nautical Almanac. These three correction factors are always positive. One needs the nofollowing information to enter the tables: LHA of Aries, DR latitude, and the month of the year. Therefore:

Enter the Polaris table with the calculated LHA of Aries (162° 03.5'). See Figure below. 2012_the_polaris_tables

The first correction, A_0,isa function solely of the LHA of Aries. Enter the table column indicating the proper range of LHA of Aries; in this case, enter the 160°-169° column. The numbers on the left hand side of the A_0 correction table represent the whole degrees of LHA \Upsilon; interpolate to determine the proper A_0 correction. In this case, LHA \Upsilon was 162° 03.5'. The A0 correction for LHA = 162° is 1° 25.4' and the A_0 correction for LHA = 163° is 1° 26.1'. The A_0 correction for 162° 03.5' is 1° 25.4'.

LHA\Upsilon 162° 03.5'
A_0 (162° 03.5') +1° 25.4'
A_1 (L = 50°N) +0.6'
A_2 (April) +0.9'
Sum 1° 26.9'
Constant -1° 00.0'
Observed Altitude 49° 31.6'
Total Correction +26.9'
Latitude N 49° 58.5'
Tabulated GHA \Upsilon (2300 hrs.) 194° 32.7'
Increment (18-56) 4° 44.8'
GHA 199° 17.5'
DR Longitude (-W +E) 37° 14.0'

To calculate the A_1 correction, enter theA_1 correction table with the DR latitude, being careful to stay in the 160°- 169° LHA column. There is no need to interpolate here; simply choose the latitude that is closest to the vessel’s DR latitude. In this case, L is 50°N. The A_1 correction corresponding to an LHA range of 160°-169° and a latitude of 50°N is + 0.6'.

Finally, to calculate the A_2 correction factor, stay in the 160°-169° LHA \Upsilon column and enter the A_2 correction table. Follow the column down to the month of the year; in this case, it is April. The correction for April is + 0.9'.

Sum the corrections, remembering that all three are always positive. Subtract 1° from the sum to determine the total correction; then apply the resulting value to the observed altitude of Polaris. This is the vessel’s latitude.

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Keywords: Polaris Sight, Latitude
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